Math, asked by suryansh2369, 1 year ago

Present age of rohit and mayank is in the ratio 11:8.8 yrs hence theie ratio is 5:4 what is present age

Answers

Answered by kushanaanandp4ac8a
1
Hey!

Let the present age of Rohit and Mayank be 11x and 8x respectively.

8years hence.

So 11x+8/8x+8= 5/4.
4(11x+8)=5(8x+8).
44x+32=40x+40.
44x-40x=40-32.
4x=8.
x=8/4=2.

So Rohit's present age=11x=11*2=22years.
Mayank's present age=8x=8*2=16years.

Hope it helps.
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