Present age of the father is 3 more than 3 times of his son's age. After 10 years father will be 10 more than twice his son's age find their present ages.
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Answered by
0
Hi ,
At present
________
Son age = x years
Father age = ( 3x + 3 ). years
After 10 years
___________
Son age = ( x + 10 ) years
Father age = ( 3x + 3 + 10 ) years
= ( 3x + 13 ) years
According to the problem given,
3x + 13 = 2( x + 10 ) + 10
3x + 13 = 2x + 20 + 10
3x - 2x = 30 - 13
x = 17
Therefore ,
At present ,
Son age = x = 17 years
Father age = 3x + 3
= ( 3 × 17 ) + 3
= 51 + 3
= 54 years
I hope this helps you.
:)
At present
________
Son age = x years
Father age = ( 3x + 3 ). years
After 10 years
___________
Son age = ( x + 10 ) years
Father age = ( 3x + 3 + 10 ) years
= ( 3x + 13 ) years
According to the problem given,
3x + 13 = 2( x + 10 ) + 10
3x + 13 = 2x + 20 + 10
3x - 2x = 30 - 13
x = 17
Therefore ,
At present ,
Son age = x = 17 years
Father age = 3x + 3
= ( 3 × 17 ) + 3
= 51 + 3
= 54 years
I hope this helps you.
:)
Answered by
0
Hey ,
son age =17 year
father age =54 year
HOPE it helped
son age =17 year
father age =54 year
HOPE it helped
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