Math, asked by niki84890, 7 months ago

Present age of veena's mother is four times veena's age. 5
Five years hence, her age will be 21 years more than veena's age. Find their present ages ?​

Answers

Answered by ƦαíηвσωStαƦ
15

\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}

\sf{\underline{\green{AnswEr:-}}}

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  • The present age of Veena = 7 years
  • The present age of Veena's mother = 28 years

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\sf{\underline{\green{Given:-}}}

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  • Present age of veena's mother is four times veena's age.Five years hence, her age will be 21 years more than veena's age.

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\sf{\underline{\green{Find:-}}}

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  • The present age of Veena = ?
  • The present age of Veena's mother = ?

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\sf{\underline{\green{Explanation:-}}}

Let present age of Veena = y years

And, Veena's mother's age = 4y years

\:\:\:\:\dag\bf{\underline{\underline \red{After\: five\: years:-}}}

  • Veena's age = (y + 5) years
  • Mother's age = (4y + 5) years

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\sf{\underline\pink{A.T.Q:-}}

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\longrightarrow \sf {4y + 5 = y + 5 + 21}

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\longrightarrow \sf {3y = 21}

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\longrightarrow \sf {y = \cancel\dfrac{21}{3} }

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\longrightarrow \sf {y = 7}

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\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}

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  • Present age of Veena's = 7 years

  • Present age of Veena's mother = 7 × 4

  • Present age of Veena's mother = 28 years

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\rule{200}{2}

Answered by Anonymous
29

Let present age of Veena = y years

And, Veena's mother's age = 4y years

After five years:−

Veena's age = (y + 5) years

Mother's age = (4y + 5) years

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A.T.Q:−

⟶ 4y+5=y+5+21

⟶3y=21

⟶y= 3/21

y =7

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Hope it will be helpful :)

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