Math, asked by rupinderkaur1145, 1 year ago

Present age of veena's mother is four times veena's age five years hence her age will be 21 years more than veena's age find their present age

Answers

Answered by satyasmithpadhy11
7

Step-by-step explanation:

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Answered by DeenaMathew
3

Veena's mother is four times the age Veena. After five years, the age of Veena's mother will be 21 years more than Veena's. What are the present ages of Veena and her mother?

The present age of veena and veena's mother is 7 and 28 years respectively.

Given:

Veena's mother is four times the age Veena. After five years, the age of Veena's mother will be 21 years more than Veena's.

To Find:

Their present ages.

Solution:

To find their present ages we will follow the following steps:

According to the question-

Let the present age of veena = x

Veena's mother's age = 4x

After five years age of veena = x + 5

After five years, the age of Veena's mother = 21 + (x+5).

After five years, the age of Veena's mother can be written as 4x + 5.

Now,

Equating the veena's mother's age we get,

21 + (x+5) = 4x + 5

26 + x = 4x + 5

26 - 5 = 4x - x

21 = 3x

x =  \frac{21}{3}  = 7

The present age of veena = 7 years

The present age of veena's mother = 7 × 4 = 28.

Henceforth, the present age of veena and veena's mother is 7 and 28 years respectively.

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