Question

Present age or abhiram is 7 times of his son's age.5 years later the product of their ages is 297. Find their agea

Answer 1

Answer:

let sons age be x

Abhiram age be 7x

five yrs later:---

son age = x+5

Abhiram age= 7x+5

A/Q

(x+5)(7x+5)=297

solve the equation and get the answer

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Answer 2

Answer:

let sons age be x

Abhiram age be 7x

5 years later :

son age = x+5

Abhiram age= 7x+5

(x+5)(7x+5)=297

7x² + 35x + 5x + 25 = 297

7x² + 40x + 25 = 297

7x² + 40x - 272 = 0

from , x= (-b±√(b^2-4ac))/2a

          x = 4

        7x = 7(4) = 28

Therefore the present age of Abhiram is 28 and present age of his son is 4