Question

present ages.
18. A playground is 30 m longer than it is wide. If its perimeter is 300 m, what is its area?
9. In the figure, all the corners are right-angled and the dimensions are as given in​

Answer 1

Step-by-step explanation:

18 let the its width be x m.

then its length be x + 30 m

perimeter of playground = 300 m

2 ( l + b ) = 300

2 ( x + 30 + x ) = 300

2 ( 2x + 30 ) = 300

4x + 60 = 300

4x = 300 - 60

x = 240 ÷ 4

x = 60

now its width is 60 m

then uts length is 60 +30 = 90m

Area of playground = l × b

= 60 × 90

= 5400 m

Answer 2

Step-by-step explanation:

Let the width/breadth be x.

Then the length is x+30

Perimeter is 2(l + b)

2(x + x + 30) = 300m => 2(2x + 30) = 300m

4x + 60 = 300m => 4x = 300 - 60

4x = 240 => x = 240/4 => x = 60

therefore, width/breadth is (x) = 60m

Then length is (x + 30) = 90m

Area is (l×b)

length = 90m ; breadth/width = 60m

therefore, Area = 90×60 = 5400sq.cm.

Answer: 5400sq.cm.

I cannot make out what you have written in

no.9, but no.18 l have understood and solved...

Sorry for no.9