Question

present ages?
19) A father is 7 times as old as his son. Two years ago, the father was 13 times as old
as his son. What are their present ages?​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

There is two answer which would you luke please mark me Brainliest.

1)

Let the present age of the son be x and that

to of his father which is 7 times =7x

Then, 2 years ago their ages :

(x-2) of son

(7x-2) of father

Given, 13(x−2)=7x−2

Then,

13x−26=7x−2

=13x−7x=26−2

6x=24

or x=4 and that of his father = 28 years

age of son=x=4years

age of father=7x=28years

Step-by-step explanation:

2)

son’s age = 4 yrs

father’s age = 28 yrs , both current.

sol : let son’s present age = x , then father’s current age = 7x;

then two years ago , son’s age = x - 2 and

father’s age = 7x - 2

now according to question, two years ago father’s age was 13 times of his son

therefore

7x - 2 = 13(x - 2)

this on solving gives

x = 4 that is son’s age

and father’s age = 7x = 28 years old.