Present ages of A and B are 20 years and 5 years respectively. After how many
years will the age of A be twice that of B?
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Let's take the no.of yrs as, x
After x yrs : A's age. = 20 + x
B
Thus, (20 + x) = 2(5+x)
= 20 + x = 10 + 2x
= 2x- x = 20 - 10
= x = 10 yrs
NOW LETS VERIFY……….
A's age after 10 yrs = 20 + 10 = 30 yrs
B's age after 10 yrs = 5 + 10 = 15 yrs
We can see that A is double B's age………
Thus the sum is solved
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Hope it helps......
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