Question

Present ages of A and B are in ratio 2:3. After 6 years the ratio will 3:4. Find their present age

Answer 1

Answer:

The present age of A is 12 years and B is 18 years.

Step-by-step explanation:

Given :

• Present ages of A and B are in ratio 2 : 3
• After 6 years, the ratio will be 3 : 4

To find :

their present ages

Solution :

Let the present age of A be 2x years and present age of B is 3x years

(as the ratio of their present ages is given as 2 : 3)

After 6 years,

A's age = (2x + 6) years

B's age = (3x + 6) years

• Their ratio = 3 : 4

A's age / B's age = 3 / 4

(2x + 6)/(3x + 6) = 3/4

4(2x + 6) = 3(3x + 6)

 8x + 24 = 9x + 18

 9x - 8x = 24 - 18

  x = 6

The value of x is 6.

A's present age :

2x = 2(6) = 12 years

B's present age :

3x = 3(6) = 18 years

Answer 2

Answer:

12 and 18 years are the present age's of A and B respectively.

Step-by-step explanation:

Given :-

Present ages of A and B are in the ratio 2 : 3

After 6 years, the ratio will be 3 : 4

To find :-

Present age's of A and B.

Solution :-

Let the age's of A and B be 2x and 3x.

After 6 years, the ratio will be 3 : 4.

After 6 years, age's of A and B will be,

2x + 6

3x + 6

ATP,

$\frac{2x+6}{3x+6} = \frac{3}{4}$

Cross multiply

3(3x + 6) = 4(2x + 6)

9x + 18 = 8x + 24

x = 24 - 18

x = 6

Hence, the present age's of A and B are,

2x = 12 years

3x = 18 years

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