Question

Present ages of Neetu and sanju are in the ratio 4:5. Eight years from now the ratio of their ages will be 5:6. Find the present ages​

Answer 1

Answer:

neetus present age is 32

sanjus present age is 40

Step-by-step explanation:

neetu's present age = 4x

sanju's present age = 5x

eight years later

neetu's age= 4x+8

sanju's age= 5x+8

4x+8=5y

4x-5y=-8 ... (1)

5x+8=6y

5x-6y=-8 ...(2)

eq(1)*5= 20x-25y=-40 ...(3)

eq(2)*4=20x-24y=-32 ...(4)

eq(3)-eq(4)

20x-25y-20x+24y=-40+32

-y=-8

y=8

substituting y in eq(1)

4x-5*8=-8

4x-40=-8

4x=-8+40

4x=32

x=32/4

x=8

neetu's present age= 4*8=32

sanju's present age=5*8=40

Answer 2

Answer:

The present ages of Neetu and Sanju are 32 years and 40 years respectively.

Step-by-step explanation:

Finding ages of Neetu and Sanju:

•  Let the present age of Neetu = 4x

              and   present age of Sanju = 5x

•  8 years later, the ages can be written as

              Age of Neetu = 4x + 8

               Age of Sanju = 5x + 8

•   Given, Ages of Neetu and Sanju 8 years later = 5:6

                 then we can write,

                      $\frac{4x+8}{5x+8} = \frac{5}{6}$

              apply cross multiplication

                  6(4x+8) = 5(5x+8)

                   24x+48 = 25x+40

       write variables in left hand side and constants in right hand side

                   24x-25x = 40-48

                            -1x = -8

                               x = $\frac{-8}{-1}$

                               x = 8

       Now we can find the present ages of Neetu and Sanju

       Substitute x = 8 in 4x and 5x

        Present age of Neetu = 4x = 4(8) = 32years

          Present age of Sanju = 5x = 5(8) = 40years

To learn more about Quadratic equations go to the link:

     https://brainly.in/question/33914668?referrer=searchResults