Present ages of Reena and Meena are in the ration 4 : 5. After 8 years, the ratio of their
ages will be 5 : 6. Find their present ages.
Answers
Answer:
Step-by-step explanation:
The present age of Reena is 32 years
The present age of Meena is 40 years.
Given: The present ages of Reena and Meena are in the ratio 4: 5. After 8 years, the ratio of their ages will be 5: 6.
To Find: The present ages of Reena and Meena.
Solution:
Let the constant between the present ages be 'x'.
So, the present age of Reena is = 4x
And, the present age of Meena is = 5x
After 8 years, the age of Reena = 4x + 8
After 8 years, the age of Meena = 5x + 8
The ratio of their ages after 8 years is = 5: 6
So, after framing an equation from the above-given conditions, we get;
( 4x + 8 ) / ( 5x + 8 ) = 5 / 6
⇒ 6 × ( 4x + 8 ) = 5 × ( 5x + 8 )
⇒ 24x + 48 = 25x + 40
⇒ 25x - 24x = 48 - 40
⇒ x = 8
The present age of Reena is = 4x = 4 × 8
= 32 years
The present age of Meena is = 5x = 5 × 8
= 40 years
Hence,
The present age of Reena is 32 years
The present age of Meena is 40 years.
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