Question

Present ages of rohit and mayank are in ratio 11:8.8years hence ratio of their ages will be 5:4.Find their present ages

Answer 1

Solutions :-

Given :
Present ages of Rohit and Mayank are in ratio 11 : 8
After 8 years, Ratio of their ages will be 5 : 4

Let the Present ages of Rohit and Mayank be 11x and 8x respectively.


According to the question,


$= > \frac{11x + 8}{8x + 8} = \frac{5}{4} \\ \\ = > 4(11x + 8) = 5(8x + 8) \\ \\ = > 44x + 32 = 40x + 40 \\ \\ = > 44x - 40x = 40 - 32 \\ \\ = > 4x = 8 \\ \\ = > x = \frac{8}{4} = 2$


Therefore,
Present Age of Rohit = 11x = 11 × 2 = 22 years
Present Age of Mayank = 8x = 8 × 2 = 16 years


Hence,
Present Age of Rohit and Mayank are 22 years and 16 years respectively.

Answer 2

Let Present age of Rohit be $11x$

Let Present age of Mayank be $8x$

According to question

$\frac{11x + 8}{8x + 8} = \frac{5}{4}$

     Cross Multiplying

4 (11x + 8) = 5 (8x + 8)

44x + 32 = 40x + 40

44x - 40x = 40 - 32

4x             = 8

x                = 2

Age of Rohit = 11x = 11 *2 = 22 years

Age of Mayank = 8x = 8*2 = 16 years