Math, asked by ayushgupta6061, 4 months ago

Present ages of Rohit and Mayank are in the ratio 11:8. 8years hence ratio of their ages will be 5:4. find their present ages.​

Answers

Answered by nandni3759
4

Answer:

let Rohit present age be 11x

let Mayank present age be 8x

After 8 years Rohit age = 11x + 8

After 8 years Mayank age = 8x + 8

ATQ

11x + 8/8x + 8 = 5/4

4(11x + 8) = 5(8x + 8)

44x + 32 = 40x + 40

44x - 40x = -32 + 40

4x = 8

x = 8/4

x = 2

Rohit age = 11x = 11(2) = 22 years

Mayank age = 8x = 8(2) = 16 years

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