Math, asked by aditibhoi4888, 9 months ago

Present ages of Rohit and Mohan are in the ratio 5:6. Ten years from now the ratio of their ages will be 6:7. Find their present ages.

Answers

Answered by rushil296
2

Answer:

Their present ages are 50 and 60 respectively

Answered by rahasohail578
1

Answer:

50,60

Step-by-step explanation:

Let present ages of Rohit and mohan be 5x and 6x respectively

After 10 years their ages will be 5x + 10 and 6x +10

A/q

\frac{5x + 10}{6x + 10}=\frac{6}{7}

6x+10

5x+10

=

7

6

By cross multiplication,

=> 7(5x + 10) = 6(6x +10)

= > 35x + 70 = 36x + 60=>35x+70=36x+60

= > 35x - 36x = 60 - 70=>35x−36x=60−70

- x = - 10−x=−10

= > x = 10=>x=10

therefore present age of Rohit => 5x = 5 x 10 = 50 present age of mohan => 6x = 60 = 60. Answer

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