Present ages of Rohit and Mohan are in the ratio 5:6. Ten years from now the ratio of their ages will be 6:7. Find their present ages.
Answers
Answered by
2
Answer:
Their present ages are 50 and 60 respectively
Answered by
1
Answer:
50,60
Step-by-step explanation:
Let present ages of Rohit and mohan be 5x and 6x respectively
After 10 years their ages will be 5x + 10 and 6x +10
A/q
\frac{5x + 10}{6x + 10}=\frac{6}{7}
6x+10
5x+10
=
7
6
By cross multiplication,
=> 7(5x + 10) = 6(6x +10)
= > 35x + 70 = 36x + 60=>35x+70=36x+60
= > 35x - 36x = 60 - 70=>35x−36x=60−70
- x = - 10−x=−10
= > x = 10=>x=10
therefore present age of Rohit => 5x = 5 x 10 = 50 present age of mohan => 6x = 60 = 60. Answer
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