Question

Present ages of sameer and anand are in the ratio of 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is anand's present age in years?

Answer 1

ages of sameer & anand =x&y respectively

(3 + x) + (3 + y) = 11x + 9y

6 + x+y = 11x+9y

10x + 8y

Answer 2

Answer:

Let the present age of Sameer be 5x and Anand be 4x respectively.

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☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies\sf \dfrac{Sameer+3}{Anand+3}=\dfrac{11}{9}\\\\\\:\implies\sf \dfrac{5x + 3}{4x + 3} = \dfrac{11}{9} \\\\\\:\implies\sf (5x + 3) \times 9= 11 \times (4x + 3)\\\\\\:\implies\sf 45x + 27 = 44x + 33\\\\\\:\implies\sf 45x - 44x = 33 - 27\\\\\\:\implies\:\underline{\boxed{\red{\bf x = 6\:years}}}\: \orange\bigstar$

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☯ $\underline{\boldsymbol{Present\: Age\:of\: Sameer\:\&\: Anand:}}$

$\bullet\:\:\textsf{Sameer = 5x = 5(6) = \textbf{30 years}}\\\bullet\:\:\textsf{Anand = 4x = 4(6) = \textbf{24 years}}$

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