Math, asked by rachnachugh12, 1 year ago

Present ages of seema and shruti are in the ratio 4:5. Eight years from now,the ratio of will be 5:6. Find their present ages.

Answers

Answered by BrainlyPrincess
96
Let the age of Seema be 4x and Shruti be 5x

Eight years from now, Seema's age will be 5x and Shruti's age will be 6x


A/q,


4x + 8 + 5x + 8 = 5x + 6x

9x + 16 = 11x

16 = 11x - 9x

2x = 16

x = \dfrac{16}{2}

x = 8 years



Present age of Seema => 4x => 4 × 8 => 32 years

Present age of Shruti => 5x => 5 × 8 => 40 years

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Answered by TheLostMonk
67
ratio of their present ages = 4 : 5

let the constant ratio be ' 'x'

so let present age of seema = 4x

and present age of shruti = 5x

after 8 years:
--------------------

age of seema = 4x + 8

age of shruti = 5x + 8

according to question,

after 8 years ratio of their ages = 5 : 6

(4x + 8 ) : ( 5x + 8 ) = 5 : 6

6 × (4x + 8 ) = 5 ( 5x + 8 )

24x + 48 = 25x + 40

x = 8

therefore ,

present age of seema = 4x = 4 × 8

= 32yrs

present age of shruti = 5x = 5 × 8


= 40 years

Answer:
-------------

seema = 32 yrs , shruti = 40 yrs
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