Math, asked by Anonymous, 7 months ago

Present ages of sita and gita are in the ratio 4 : 5, Eight years from now the ratio of

their ages will be 5 : 6 Find their present ages.​

Answers

Answered by parasharpraveen244
7

Answer:

let age expressed in 'X'

then present age 5x:4x

after 3 years it becomes

{5x + 3}{4x + 3} (5x + 3) \times 9 = (4x + 3) \times 11 \\ 45x + 27 = 44x + 33 \\ x = 6 \\ geeta \: age \: = 6 \times 4 = 24 \: years \\ seeta \: age \: = 6 \times 5 \: = 30 \: years\end{gathered}

=

4x+3

5x+3

=

9

11

(5x+3)×9=(4x+3)×11

45x+27=44x+33

x=6

geetaage=6×4=24years

seetaage=6×5=30years

Answered by 1346sathyaaru05
0

Answer:

Present age of Sita = 32 years

Present age of Gita = 40 years

Step-by-step explanation:

Let ages of them be x

According to question,

4ₓ+8+5ₓ+8=5ₓ+6ₓ

9ₓ+16=11ₓ

11ₓ–9ₓ=16

2x=16

x= \frac{16}{2}

x=8

Therefore, Present age of Sita=4x 4x8 32 years

Present age of Gita=5x 5x8 40years

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