Math, asked by mrwinner0201, 17 days ago

present Mahesh's age (in years) is 2 more than the square of his son Varun's age. When Varun grows to his father's present age, Mahesh's age would be one year less than 10 times the present age of Varun. Using the above information answer the following questions. (1) Mahesh's present age is

Answers

Answered by chahaldilpreet423
0

Answer:

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Step-by-step explanation:

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Answered by dnjfjsgskxvcndknc
0

Answer:

bro I don't know but I think I will try to answer wait

Step-by-step explanation:

Answer

Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x

2

years.

Swati's present age =(x+7) years, Varun's present age=(5x

2

+7) years

Three years hence, we have

Swati's age (x+7+3) years =(x+10) years

Varun's age =(5x

2

+7+3)=(5x

2

+10)

It is given that three years hence Swati's age wil be

5

2

of Varun's age

∴x+10=

5

2

(5x

2

+10)

⇒x+10=2x

2

+4

⇒2x

2

−x−6=0

⇒2x

2

−4x+3x−6=0

⇒(2x+3)(x−2)=0

⇒x−2=0⇒x=2

Hence Swati's present age =(2+7) years =9 years

Varun's present age =(5×x

2

+7) years =27 years

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