present the sum father's and son age is 50 years after 5 years the age of father becomes 3 trimester age of his son
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let x be fathers age and y be sons age
acc to the question
x+y=50---(1)
after 5yrs
fathers age=x+5 yrs
sons age=y+5yrs
acc to condition
x+5=3(y+5)
x+5=3y+15
x-3y=10---(2)
:.subtracting equation 1from 2
x-3y=10
(-)x+y=50
----------------
-4y=-40
:.y=10substituting value of y in equation 2
x-3(10)=10
x=40
:. Sons age is 10yrs and fathers age is 40yrs
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Let Father's age be F and Son's age be S
then 5 years ago,
F−5=7(S−5)
F=7S−30
5 years hence,
F+5=3(S+5)
F=3S+10
Thus, 7S−30=3S+10
4S=40 or S=10
and, F=40 years
Father's age is 40 years
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