Question

Press the stem of an excited tuning fork of frequency 512 Hz on a table having

a natural frequency of 384 Hz. a) What is the frequency of vibration of the table at this instance? (1)

b) What is the change in the the loudness of the sound produced? Why? (1)

c) What phenomenon of sound would you observe if you press a tuning fork of natural

frequency 384 Hz on the table? Explain. (2)

Answer 1

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Question :-

Press the stem of an excited tuning fork of frequency 512 Hz on a table having a natural frequency of 384 Hz.

a) What is the frequency of vibration of the table at this instance? (1)

b) What is the change in the the loudness of the sound produced? Why? (1)

c) What phenomenon of sound would you observe if you press a tuning fork of natural  frequency 384 Hz on the table? Explain. (2)

Answer :-

$\left[\begin{array}{ccc}Answer\\&of&&\\&A\end{array}\right]$

• The frequency of vibration of the table at this instance is 512 Hz

$\left[\begin{array}{ccc}Answer\\&of&&\\&&B\end{array}\right]$

• As Surface area of the table is more  the loudness of the sound produce  increase rapidly

$\left[\begin{array}{ccc}Answer\\&of&&\\&&C\end{array}\right]$

• When I press a tuning fork of natural frequency 384 Hz on the table I observe the  phenomenon of sound that is  Resonance

• It means that the frequency of  tuning fork and table is equal that is nothing but  384 Hz

• Therefore , the  amplitude of vibration of the table increases

• As a result the loudness increases

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