Question

Pressure inside two soap bubbles is 1.01 and 1.02 atmospheres. ratio between their volume is

Answer 1

HEY DEAR ...

PM

P1=10power5 pa,change in p1 is=1.01-1=1أ—10power3.
rnP2=1.02أ—10power5.changeinp2=(1.02-1)أ—10power5=2أ—10power5.
rnP inversly related to r.=p2:p1=r1:r2=2:1
rnV1:v2=r1power3 :r2power3=8:1

HOPE , IT HELPS ...

Answer 2

Answer:

8:1

Explanation:

excess pressure in  first drop =1.01-1=0.01

excess pressure in  second drop=1.02-1=0.02

p is inversely proportional to r

r2^3/r1^3=0/02^3/0.01^3

=8:1