Question

Pressure of 1 g of an ideal gas A at 27°c is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.

Answer 1

Explanation:

weight of first gas is ,w1=1g

pressure of first gas is =2bar

volume and temperature is same or constant for both gas

weight of second gas ,w2=2g

pressure of second gas =3 bar

then, according to ideal gas equation

pv=NRT

v,Tand R is constant for both

so,P1=N1/P2=N2...Eq(1)

number of moles of first gas is N1=W1/M1=1/M1

number of moles of second gas is N2=W2/M2=2/M2

putting the value of N1 and N2 in eq(1)

2/3=1/M1/2/M2

2/3=1/M1*M2/2

2/3=1M2/2M1

4M1=3M2

M1/M2=3/4

i hope it is helpful!!