Question

pressure of 1gram of ideal gas A is 2 bar at 20 degree Celsius is and another gas Bis introduced to the flask at the same temperature pressure became 3bar if Ma=16 and Mb=?
a)16
b)32
c)48
d)64
please tell the answer
thank you

Answer 1

Answer:

M' = 4M

Explanation:

Let M and M' be the molar masses of ideal gases A and B respectively.

The number of moles of gas A and B are

1/M and 2/M' respectively.

Let P and P' be the pressures of gases A and B respectively.

P=2 bar

P+P′=3 bar

P ′ =3−2=1 bar

The ideal gas equations for two gases A and B are,

PV=nRT......(i)

P′V=n′RT......(ii)

Divide equation (i) by equation (ii).

P / P' = n / n'

= 1×M/2×M′

= M'/2M

M'/M = 2 (P/P')=2×2/1=4

M ′ = 4M

Hope It Helps!!!!