Question

pressure of 20L gas at constant temperature is 2atm what will be new volume if pressure is increased to 3atm at the same temperature

Answer 1

Answer:

the new volume is 13.33 lit.

Explanation:

Let $P_{1} =2 atm$  , $P_{2}=3 atm$

      $V_{1} =20 lit$   ,  $V_{2} = ?$

Given that , T is constant.

Applying Boyle's law, $P_{1}V_{1}=P_{2} V_{2}$

                             =>   2*20 =3*$V_{2}$

                             =>   $V_{2}$ = 13.33 lit.