Question

Pressure on a swimmer 20m below the surface of water

Answer 1

Answer:

good evening here's your answer

Explanation:

Explanation: Here h = 20 m ρ = density of water = 1000 kg/m3

 atmospheric pressure = Pa = 1.01 × 105 Pa

Hence pressure below surface = Pa + hρh

= 1.01 × 105 + (20 × 1000 × 10) = 1.01 × 105 + 2 × 105  = 3.01 × 105 Pa

As 1 atmosphere = 1.01 × 105 Pa

Hence pressure = 3.0 atmosphere = 3 atm.

i hope that's the answer to the question

thanks