Question

Pressure volume relation for a monoatomic gas undergoing adiabatic expansion

Answer 1

we know, for adiabatic expansion
$PV^{\gamma}$ = K
where P is the pressure of gases
V is the volume of gases.
$\gamma$is the atomicity of gas.
and K is constant.

for monoatomic gas ,
$\gamma$ = 5/3 ≈ 1.667

so, relation between pressure and volume for a monoatomic gas under adiabatic expansion is given as $PV^{1.667}=K$