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Q-3
The ratio of the present ages of Preeti and her daughter is 8:1. If the difference in their ages is 28 years
Find the sum of their ages after two years. .
36 years
40 years
42 years
38 years
N
Answers
The sum of their ages will be 40
Step-by-step explanation:
Given:
the ratio of present ages of Preeti & her daughter is 8: 1
the difference between their ages is 28 years
To find:
the sum of their ages after two years
Solution:
the ratio of their ages is 8: 1
Let's take a multiple common y
Thus, the ages are now 8x & 1x
The difference between their ages is 28 years
∴ 8x - 1x = 28
Solving this further
∴ 7x = 28
∴ x = 28/7
∴ x = 4
Thus, Preeti's daughter's present age is x years = 4 years
Now, Preeti's present age = 8x = 8 (4) = 32 years
After two years the ages will be
Preeti's age = 32 +2 = 34 years
Preeti's daughter's age = 4 + 2 = 6 years
The sum of their ages will be
= 34 + 6
= 40 years
Thus, two years later the sum of Preeti and her daughter's age will be 40
#SPJ3
Answer:
The required sum of their ages is 40 years.
Step-by-step explanation:
Given:-
The ratio of the present ages of Preeti and her daughter is 8:1.
The difference between their ages is 28 years.
To find:-
The sum of their ages after years.
According to the question,
Let the common ratio be x.
Since the ratio of the present ages of Preeti and her daughter is 8:1. i.e.,
The present of Preeti = 8x
And the present age of her daughter = x
Also,
The difference between their ages is 28 years, i.e.,
8x - x = 28
7x = 28
x = 28/7
x = 4
Hence,
The present age of Preeti = 8x
= 8(4)
= 32 years
The present of her daughter = x
= 4 years
After 2 years,
The age of Preeti will be,
= 32 + 2
= 34 years
And the age of her daughter will be,
= 4 + 2
= 6 years
Then, the sum of their ages after 2 years = 34 + 6
= 40 years
Therefore, the required sum of their ages is 40 years.
#SPJ3