Question

prg in java to check whether number contains only odd digits or not.
please give answer fast​

Answer 1

Answer:

Program:-

import java.util.*;

public class Main

{

public static void main(String args[])

{

Scanner in=new Scanner(System.in);

int n,a,f=0;

System.out.println("Enter the number:");

n=in.nextInt();

while(n!=0)

{

a=n%10;

if(a%2==0)

{

f=1;//if digits at any iteration is found so f is 1 and the loop is terminated

break;

}

n=n/10;

}

if(f==0)

System.out.println("The number contains only odd number of digits");

else

System.out.println("The number does not contain odd number of digits");

}

}

Output is attached:

• 135 contains all odd digits so it prints all odd digits.
• 123 does not contains all odd digits so it prints it doesn't have odd digits.

Answer 2

Answer:

import java.util.*;

class Num{

public static void main (String ar []){

Scanner sc=new Scanner (System.in);

int n=sc.nextInt(); //Accepting input

int c=0,C1=0;

while(n!=0){

C1++;

if((n%10)%2!=0)

c++;

n/=10;

}

if(c==C1)

System.out.println("Yes");

else

System.out.println("No");

}

}