Question

price of a diamond is in the proportion to the square of its weight. a diamond costing rs. 216000 breaks into three pieces. if the weight of the three pieces in the ratio of 1:2:3 finds the loss due to this breakage.
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Answer 1

Hey mate,

Cost of diamond =k(weight) 2

8000=k(10)2

k= 1008000

=80

Diamond was broke into two pieces =

3x+2x=10,

5x=10⇒x=2

Ist part: 3x=6

IInd part: 2x=4

Ist part; cost⇒80×36=2880

IInd part; cost⇒80×16=1280

Total cost = 2880+1280=4160

So loss = 8000−4160=3840

$(So.the.loss ) {}^{}$

3840

Hope it helps...

$( Itz ❤Aakanksha❤ here! ) {}^{}$