Price that n²-n is divisible by 2for every positive integer n
sivaprasath:
Did you meant Prove ?
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n²-n
=n(n-1)
So n and (n-1) are two consecutive integers
Therefore for any value of 'n'
Either n or (n-1) will be an even number
So n²-n is divisible by 2 for any value of 'n'
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