Question

pricilap value of sin^-1(sin4pi/5)​

Answer 1

sin inverse(sin4π/5)

=sin inverse sin 4π/5

=4π/5

your answer

Answer 2

Given :   Sin⁻¹ ( Sin 4π/5 )

To Find : Value of Sin⁻¹ ( Sin 4π/5 )

Solution:

Sin⁻¹ ( Sin 4π/5 )

as we know that

Sinα = Sin(π - α)

α = 4π/5

=> Sin (4π/5) = Sin ( π  - 4π/5)

=>  Sin (4π/5) = Sin ( (5π  - 4π)/5)

=>  Sin (4π/5) = Sin ( π/5)

Sin⁻¹ ( Sin 4π/5 )

= Sin⁻¹ ( Sin π/5 )

= π/5

Sin⁻¹ ( Sin 4π/5 ) = π/5   = 36°

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