Primary and secondary alcohols on action of
reduced copper give
(a) Aldehydes and ketones respectively
(b) Ketones and aldehydes respectively
(c) Only aldehydes
(d) Only ketones
Answers
Answered by
2
Answer:
a. will be the correct answer
Answered by
2
(a) Aldehydes and ketones respectively
Explanation:
Primary and secondary alcohols on action of reduced copper will give aldehydes and ketones, respectively.
Primary alcohol: R-CH2OH ----Cu--> CHO + H2 (aldehyde is formed)
Secondary alcohol: R-cH(OH)- R ---Cu---> R-C(O)-R + H2 (ketone is formed)
Hence, option A is the correct answer.
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