Question

Primary and secondary valencies of Cr in [Cr(H20)4C12]CI. 2H2O
respectively are​

Answer 1

Explanation:

Given -

• [Cr(H₂O)4Cl₂]Cl•2H₂O

To Find -

• Primary valency & secondary Valency

Solution -

As we know that -

• Primary Valency is equal to Oxidation number (O.N.) of the central metal.

And

• Secondary Valency is equal to Co-ordinarion number (C.N.) of central metal.

Then,

Primary Valency =

→ x + 0×4 - 1×2 - 1 + 2×0 = 0

→ x = +3

And

Secondary Valency =

• Ligan × Denticity

→ 1×4 + 1×3

→ 4 + 3

→ 7