primary of a transformer has 20,000 turns and the secondary has 30,000 turns. 160v AC is applied at the primary of the transformer. what is the voltage available at secondary of the above transformer?. if the number of turns in the secondary transformer is greater than that in the primary then more voltage is induced in the secondary. why?. how much power must be supplied to the primary of the transformer so that 500w power is obtained from secondary?
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First we use the fact that the ratio of the voltage on the secondary and on the primary will be the same as the ratio of the number of turns of both coils,
⇒u=u1u2=N1N2
We evaluate the unkown secondary voltage -
⇒u2=N1N2u1
We substitute the given values -
⇒u2=50010×120v=2.4v
Hence, the answer is 2.4v.
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