Question

prime factorisation of 72,96 explain it...​

Answer 1

HERE IS YOUR ANSWER USER.

Answer 2

SolutioN :

Let Number be,

• N1 = 72.
• N2 = 96.

Now, Prime factorisation of N1.

$\begin{array}{r | l} 2 & 72 \\ \cline{2-2} 2 & 36 \\ \cline{2-2} 2 & 18 \\ \cline{2-2} 3 & 9 \\ \cline{2-2} 3 & 3 \\ \cline{2-2} & 1 \end{array}$

Now, Prime factorisation of N2.

$\begin{array}{r | l} 2 & 96 \\ \cline{2-2} 2 & 48 \\ \cline{2-2} 2 & 24 \\ \cline{2-2} 3 & 12 \\ \cline{2-2} 2 & 6 \\ \cline{2-2} 3 & 3 \\ \cline{2-2} & 1 \end{array}$

# We can Also Write as,

$\tt \dagger \: \: \: \: \: 72\leadsto2 \times 2 \times 2 \times 3 \times 3.$

$\tt \dagger \: \: \: \: \: 96\leadsto2 \times 2 \times 2 \times 2 \times 2 \times 3.$

Extra InformatioN :

Let Find Highest Common factor ( HCF ) & Least common multiple ( LCM )of ( N1 and N2 )

★ HCF → 2 * 2 * 2 * 3 = 24.

★ LCM → 2 * 2 * 2 * 3 * 3 * 2 * 2 = 288.