Question

prime factorization of 108 and the subtraction of the factors must be 28

Answer 1

Prime factorisation:
1008 = 2 × 2 × 2 × 2 × 3 × 3 × 7 = 24 × 32 × 72 × 2 × 2 × 2 × 3 × 3 × 7 = 24 × 32 × 7
1080 = 2 × 2 × 2 × 3 × 3 × 3 × 5 = 23 × 33 × 52 × 2 × 2 × 3 × 3 × 3 × 5 = 23 × 33 × 5
HCF = Product of  smallest power of each common prime factor in the number
         = 23× 3223× 32 = 72

Answer 2

2x2x3x3x3 is the prime factorization of 108