Question

Prime Factorization of 9000
What is the prime factorization of 9000?

Answer 1

The Prime Factors of 9000: 2³ • 3² • 5³ i.e. 2 × 2 × 2 × 3 × 3 × 5 × 5 × 5

Answer 2

$\sf{\underline{Prime\:factorization\:of}}$: 9000

$\begin{array}{r | l} 2 & 9000 \\ \cline{2-2} 2 & 4500 \\ \cline{2-2} 2 & 2250 \\ \cline{2-2} 3 & 1125 \\ \cline{2-2} 3 & 375 \\ \cline{2-2} 5 & 125 \\ \cline{2-2} 5 & 25 \\ \cline{2-2} 5 & 5 \\ \cline{2-2} & 1 \end{array}$


$\sf{\underline{Therefore:}}$

The prime factors are: $2^{3}$ × $3^{2}$ × $5^{3}$


$\sf{\underline{That\:is:}}$

2 × 2 × 2 × 3 × 3 × 5 × 5 × 5 = 9000


$\sf{\underline{What\:is\:prime\:factorization?}}$

$\implies$ This method is used to break a number down into the set of prime numbers.

$\implies$ When we multiply all these numbers together, it gives us the original number.