Question

Primes.
Write a quadratic polynomial, sum of whose zeroes is 2 and product is -8.​

Answer 1

Answer:

We know that ,

x^2-(sum of zeroes)x+product of zeroes=0

=x^2-2x+(-8)

=x^2-2x-8

Answer 2

➟ Given :

Sum of zeroes = 2

Product of zeroes = -8

➪ Quadratic formula -

➮$= x {}^{2} - (sum \: of \: zeroes \: )x \: + \: product \: of \: zeroes$

➮Lets put the values :

$= x {}^{2} - (2)x + ( - 8) \\ ➤ = x { - 2x - 8}^{2}$

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Hope it's helpful!

@ Dhruvshi23!