Math, asked by manmeet13Op, 7 months ago

Principal=1500 Rate=12%p.a.
Time=3years3month help me to solve this by easy explanation​

Answers

Answered by Anonymous
5

Step-by-step explanation:

CaseI

P=Rs 1500 r=12% p.a t=1 year

Interest =

100

1500×12×1

=Rs180.

∴A=Rs1680.

CaseII

P=Rs 1680 r=12% p.a t=1 year

Interest =

100

1680×12×1

=Rs201.

∴A=Rs1881.60.

CaseIII

P=Rs 1881.60 r=12% p.a t=1 year

Interest =

100

1881.60×12×1

=Rs225.80.

∴A=Rs2107.40.

CaseIV

P=Rs 2107.40 r=12% p.a t=

12

3

=

4

1

years

Interest =

100

2107.40×12

×

4

1

=Rs 63.22.

∴A=Rs 2170.62.

Compound interest is Rs 670.62

Answered by Anonymous
3

☆ANSWER☆

CaseI

P=Rs 1500      r=12% p.a     t=1 year

Interest =1001500×12×1=Rs180.

∴A=Rs1680. 

CaseII

P=Rs 1680      r=12% p.a     t=1 year

Interest =1001680×12×1=Rs201.

∴A=Rs1881.60. 

CaseIII

P=Rs 1881.60      r=12% p.a     t=1 year

Interest =1001881.60×12×1=Rs225.80.

∴A=Rs2107.40. 

CaseIV

P=Rs 2107.40      r=12% p.a     t=123=41 years

Interest =100

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