Question

principal=15000, rate=8p.c.p.a, time= 2years . What is the interest and amount ?​

Answer 1

= 15000×8×2/100= 2400

amount = principal + interest

= 15000+2400 = 17400

Answer 2

Answer:

) Here, P = ₹ 2000; R = 5 % ; N = 2 years

A=P(1+R100)N =2000(1+5100)2 =2000(105100)2 =2000(2120)2 =2205 Rupees∴ Compound Interest after 2 years,I = Amount − Principal =2205−2000 =205 RupeesA=P1+R100N =20001+51002 =20001051002 =200021202 =2205 Rupees∴ Compound Interest after 2 years,I = Amount - Principal =2205-2000 =205 Rupees

Hence, Amount = ₹ 2205 and Compound interest = ₹ 205.

(2) Here, P = ₹ 5000; R = 8 % ; N = 3 years

A=P(1+R100)N =5000(1+8100)3 =5000(108100)3 =5000(2725)3 =6298.56 Rupees∴ Compound Interest after 3 years,I = Amount − Principal =6298.56−5000 =1298.56 RupeesA=P1+R100N =50001+81003 =50001081003 =500027253 =6298.56 Rupees∴ Compound Interest after 3 years,I = Amount - Principal =6298.56-5000 =1298.56 Rupees

Hence, Amount = ₹ 6298.56 and Compound interest = ₹ 1298.56

(3) Here, P = ₹ 4000; R = 7.5 % ; N = 2 years

A=P(1+R100)N =4000(1+7.5100)2 =4000(1+751000)2 =4000(10751000)2 =4000(4340)2 =4622.50 Rupees∴ Compound Interest after 2 years,I = Amount − Principal =4622.50−4000 =622.50 RupeesA=P1+R100N =40001+7.51002 =40001+7510002 =4000107510002 =400043402 =4622.50 Rupees∴ Compound Interest after 2 years,I = Amount - Principal =4622.50-4000 =622.50 Rupees

Hence, Amount = ₹ 4622.50 and Compound interest = ₹ 622.50