Question

Principal=4000, intrest = 4300, rate= 7½ find the time

Answer 1

answer

$principal = 4000 \\ a = 4300 \\ r = 7 \frac{1}{2} = \frac{15}{2} = 7.5 \\ n(time) =1yr \\ a = p(1 + \frac{r}{100}) {}^{n} \\ 4300 = 4000(1 + \frac{7.5}{100} ) {n}^{} \\ \frac{4300}{4000} = 1.075 \times n \\ 1.075 = 1.075 \times n \\ n = \frac{1.075}{1.075} \\ n = 1yr$