Question

principal-6400RS ,R-7℅,T-225days Find the intereset​

Answer 1

ANSWER

Given,  SI=4800

            CI=5088

Say the principal amount was P and rate of interest is r% p.a for two years

∴   SI=100PT=100P×2×r

⇒4800=1002Pr

⇒240000=Pr⟶(1)

Similarly CI=P(1+100r)2−P

⇒5088=P[(1+100r)2−1]⟶(2)

Substituting (1) in (2) we get

5088=r240000[1+1002r2+1002r−1]

⇒2400005088=1002r+1002

⇒0.021