Question

Principal and general solutions cosx=-√3/2​

Answer 1

Step-by-step explanation:

We have,

$\cos(x) = - \frac{ \sqrt{3} }{2}$

$\implies\cos(x) = \cos( \frac{5\pi}{6} )$

$\implies \: x = 2n\pi ± \frac{5\pi}{6}$

$PRINCIPLE\:\ SOLUTION: \\ x= 2n\pi ± \frac{5\pi}{6}$

$GENERAL\:\ SOLUTION: \\ x= \frac{5\pi}{6}, \frac{7\pi}{6}$