Question

Principal = P = ₹ 25000, R = 8 p.c.p.a, T = 3 years. Find Simple Interest(I). *​

Answer 1

Answer :-

Given :-

• Principal = ₹ 25000
• Rate of interest = 8% p.a.
• Time = 3 years

To Find :-

• Simple interest, I

Solution :-

We know that,

Simple interest = Principal × Rate of interest × Time / 100

Here, we have principal, rate of interest and time. So, by simply substituting the value, we can find simple interest -

→ I = P × R × T / 100

→ I = 25000 × 8 × 3 / 100

→ I = 250 × 8 × 3

→ I = 2000 × 3

→ I = 6000

Simple interest = ₹ 6000

Answer 2

Given :-

• Principal = ₹ 25,000
• Rate of Interest = 8% p.a
• Time = 3 years

To find :-

• Find the Simple Interest, l

★ $\large\underline{\frak{As~we~know~that,}}$

• $\boxed {\sf{Simple \: Interest = \frac{P \: \times \: R \: \times \: T}{100} }}$$\large\star$

Solution :-

• Principal, Rate and Time

• Substituting the value,

:$\implies$l = $\large{\sf{\frac{P \: \times \: R \: \times \: T}{100}}}$

$~~~~~$:$\implies$l = $\large{\sf{\frac{25,000 \: \times \: 8 \: \times \: 3}{100}}}$

$~~~~~~~~~~$:$\implies$l = 250 × 8 × 3

$~~~~~~~~~~~~~~~$:$\implies$l = 2,000 × 3

$~~~~~~~~~~~~~~~~~~~~$:$\implies$${\underline{\boxed{\pink{\frak{l~=~6,000}}}}}$★

$\therefore$ Hence,

• The Simple Interest is = $\large{\rm\underline{₹~6,000}}$