Question

Principal =Rs 1280, Rate = 12
2,Time = 3 years 3 month.
%p.a.​

Answer 1

Answer:

▶ Answer :-

→ SI = 88.

→ Amount = ₹1368.

▶ Explanation :-

▶ Given :-

→ Principal (p) = ₹1280 .

→ Time (t) =  years = 2.5 years .

→ Rate (R) =  % = 2.75 % .

▶ To find :-

→ Simple Interest (SI) .

→ Amount .

▶ Solution :-

And, we know that :-

°•° Amount = SI + principal .

= 88 + 1280.

✔✔ Hence, it is solved ✅✅.

Step-by-step explanation:

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Answer 2

Correct question :-

• Principal = Rs 1280, Rate = 12 % P.A Time = 3 years 3 months. Find S.I?

Answer :-

• Simple Interest = 499.2 rupees.

Given :-

• Principal = 1280.
• Rate = 12% P.A.
• Time = 3 years 3 months.

To find :-

• S.I.

Step by step explanation :-

Detailed explanation of solution :-

Let's understand!

Principal , Rate and Time are given to us. In the ques, We are asked to find intrest.

How to solve ?

We know this formula, PTR/100. Let's use this and form a equation by the information given to us.

Calculations :-

$\sf \dfrac{ 1280 \times \dfrac{13}{4} \times 12 }{100}$

Cutting off zero from up and down,

$\sf \dfrac{ 128 \times \dfrac{13}{4} \times 12 }{10}$

Simplifying 128 and 10,

$\sf 12.8 \times \dfrac{13}{4} \times 12$

We will multiply the remaining numbers,

$\sf 12.8 \times \dfrac{13}{1} \times 3$

$\sf 12.8 \times 13 \times 3$

$\leadsto \sf 499.2$

Therefore, Simple Interest = 499.2 rupees.