Question

principal=rs.2500 time= 3years rate=6%p.a
find the compound intrest

Answer 1

Answer:

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Step-by-step explanation:

$so \: here \\ principal \: amount \: (P) = Rs.2500 \\ Time \: (n) = 3.years \\ Rate \: of \: interest \: (I) = 6\% \: p.a$

$so \: we \: know \: that \\ compound \: interest = P \times (1 + \frac{I}{100} ) {}^{n} \\ \\ = 2500(1 + \frac{6}{100} ) {}^{3} \\ \\ = 2500( \frac{100 + 6}{100} ) {}^{3} \\ \\ = 2500( \frac{106}{100} ) {}^{3} \\ \\ = 2500 \times \frac{106}{100} \times \frac{106}{100} \times \frac{106}{100} \\ \\ = 2500 \times \frac{(106) {}^{3} }{1000000} \\ \\ = \frac{(106) {}^{3} }{400} \\ \\ = \frac{106 \times 106 \times 106}{400} \\ \\ = \frac{53 \times 53 \times 53}{50} \\ \\ = \frac{148877}{50} \\ \\ = 2977.54 \: ₹ \\ \\ hence \: compound \: interest \: is \: 2977.54 \: ₹$