Question

Principal= Rs.50,000, Interest= Rs.6,000. Find the amount​

Answer 1

Answer:

x2/a2 + y2/b2 =2

Step-by-step explanation:

50.000000999090009⁸38383

Answer 2

Here, Principal (P) = Rs. 50,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 years

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100}

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280=

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 100

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R=

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100 \Rightarrow\ R\ =\ 0.25\%⇒ R = 0.25%

,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100}\Rightarrow R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100 \Rightarrow\ R\ =\ 0.25\%⇒ R = 0.25%Hence, the rate of interest on sum is 0.25%.