Question

Principal = Rs. 62500, rate = 12 % p.a. and time = 3 years. Find the Amount if the interest is compounded Annually.​

Answer 1

Solution:-

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◍ Here, the question has given us the principal, rate of interest and time that is Rs. 62,500, 12% per annum and for 3 years respectively. Now, the question has asked us to find the compound interest on it. So to get the answer we need to apply the formula of amount first then we will subtract the principal from amount to get CI.

ANSWER:-

◈ The amount is Rs. 87,808.

◈ The CI is Rs. 25,308.

GIVEN:-

☆ Principal = Rs. 62,500

☆ Rate of Interest = 12% per annum

☆ Time = 3 years

TO FIND:-

↠Amount he will get back = ?

FORMULA:-

⬤ Amount = P[1 + (R / 100)]^t

⬤ CI = Amount - Principal

SOLVING BY APPLYING THE FORMULA:-

⇨ Principal = Rs. 62,500

⇨ Rate = 12%

⇨ Time = 3 years

⇨ Amount = P[1 + (R / 100)]^n

➢ Amount = 62,500[1 + (12 / 100)]³

➢ Amount = 62,500[100 + 12 / 100]³

➢ Amount = 62,500[112 / 100]³

➢ Amount = 62,500 × 112 / 100 × 112 / 100 × 112 / 100

➢ Cancelling the zeros.

➢ Amount = 625 × 112³ / 100²

➢ Amount = 87,808

➢ Amount = Rs. 87,808

Thus, the amount is Rs. 87,808.

⇨ Compound Interest = Amount - Principal

➢ CI = 87,808 - 62,500

➢ CI = 87,808 - 62,500 = 25,308

➢ CI = Rs. 25,308

Hence, we got the answer. The CI is Rs. 25,308.

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Answer 2

Answer:

P = 62500

R = 12%

T = 3 years

$a = p(1 + \frac{r}{100} ) {}^{t}$

$= 62500(1 + \frac{12}{100} ) {}^{3}$

Now, we will cut 12 from 2 = 6 , 6 from 2 = 3

And we will cut 100 from 2 = 50 , 50 From 2 = 25

$= 62500(1 + \frac{3}{25} ) {}^{3}$

3 + 25 = 28

$= 62500( \frac{ \\ 28}{25} ) {}^{3}$

$= 62500 \times \frac{28}{25} \times \frac{28}{25} \times \frac{28}{25}$

$= 87808$

$compound \: interest = a - p$

$= 87808 - 62500$

$= 25308$

Answer is 25308

Answer 3

Answer:

Explanation:.....