Question

principal=rs6000
time=3years 9months
interest=rs1155 find rate



solve this step by step plz​

Answer 1

Answer:

heya m8! this is ur answer.

720 rupees is your answer

The formula for finding simple intrest is

\frac{principle \times rate\% \times time }{100}

100

principle×rate%×time

According to Question

Rate of interest (R) = 6%

Time (T) is always taken in years= {2}2

Principal (P) = 6,000

According to the formulae

\frac{6000 \times 6 \times 2}{100 } = 720 \: rupees

100

6000×6×2

=720rupees

So simple intrest = 720 rupees

Related formulas

Related formulasPrincipal =

\frac{intrest \times 100}{rate\% \times time \: period}

rate%×timeperiod

intrest×100

Rate =

\frac{intrest \times 100}{principal \times time}

principal×time

intrest×100

Time =

\frac{intrest \times 100}{principal \times rate}

principal×rate

intrest×100

Amount= Principal + Simple intrest

Answer 2

$5.13 \%$

Step-by-step explanation:

$Given, \\ P = ₹6000 \\ t = 3 year 9 month = 15/4 \: year \\ S.I = ₹1155\\now \: \: \: \boxed{S.I = \frac{p \times r \times t }{100} } \\ 1155 = \frac{6000 \times r \times 15}{4 \times 100} \\ r = \frac{1155 \times 4 \times 100}{6000 \times 15} = \frac{77}{15} \\ r = 5.13$