Question

principal solution of tanx=-1/root 3

Answer 1

HEYA!!
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$tan \: x \: = \frac{ - 1}{ \sqrt{3} } \\ \\we \: know \: \: that \: \\ tan \: \frac{\pi}{6} = \frac{1}{ \sqrt{3} } \\ \\ thus \: \: tan \: (\pi - \frac{\pi}{6} ) = - tan \frac{\pi}{6} \\ also \: \: tan \: (2\pi - \frac{\pi}{6} ) = - tan \: \frac{\pi}{6} \\ \\ thus \: \: principal \: solutions \: are \: \frac{5\pi}{6} and \: \frac{11\pi}{6}$
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